- By the eliminations of one or more than one variables from the given simultaneous equations, we get such a relation which is __________ of that variable.
- At least ________ equations are required for elimination of one variable.
- In elimination, both equations should have the ________ that has to eliminate.
- Eliminant or relation shows that the solution set of both equations is not _________.
- The relation free from x for x-b = 0 and x-d = 0 is ___________.
- The relation free from x for xt = s and x = t is ___________.
- The relation free from t for at = x and 2at = y is ______________.
- The relation independent of ‘x’ for equations x + 1/x = a and x2 + 1/x2 = b2 is ________.
- Te relation independent of ‘x’ for equations x + 1/x = m and x3 + 1/x3= n is __________.
- The relation free from ‘t’ for equations x + t = 3p and x – t = 4q is ____________.
- The eliminant by eliminating ‘m’ for equations m + bc = x and m – ad = y is _______.
- The eliminant by elimination y for equations y2 = s and y3 = r is ____________.
- The relation free from y for equation y = 1/2m and y = 4n is ____________.
- The equation y + 4 = 9 is y –5 =6 are not true for a __________ value of y.
- A relation independent of ‘t’ from equations t5 = d and t3 = b is ___________.
- A relation independent of ‘x’ from equations x3 – b = 0 and x2 + d = 0 is ________.
- The relation free from ‘x for equations x2 + 1 = 3m2 and x4 + 1 = n4 is __________. x2 x4
- The relation free from ‘y’ for equations √y – 1 = √a and y + 1/y = b is ___________. √y
- The relation from ‘y’ for equation x = √2 t and y = √7 t is ____________.
- The relation free from ‘x’ for equations x + a = 0 and x2 + y2 = b2 is _________.
- The eliminant by elimination ‘u’ for equations v = u –t and u2 = 2vt.
- The eliminant by eliminating ‘y’ for equations y3 + 1/y3 = m and y3 – 1/y3 = n is _______.
- The relation free from ‘x’ for equations x – 1 = m and x3 – 1 = 4n3 is _________ x x3
- The relation free from ‘x’ for equations x = 3p and x = 1 is __________ 7t
- The relation free from ‘y’ for equation y2 – 1/y2 = a and y4 + 1/y4 = b4.